Milliampere-seconds (mAs)

Changed by Andrew Murphy, 11 Apr 2017

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Milliamperage-seconds more commonly known as mAs is a measure of radiation produced (milliamperage) over a set amount of time (seconds) via an x-ray tube. It directly influences the radiographic density, when all other factors are constant.An increase in mA results in a higher production of elections that are inside the X-ray tube wich will, therefore, increase the quantity of radiation; more radiation will cause more photons reaching the detector and hence the density will increase. The time factor (s) is a measure of the electrons production duration in the tube; meaning 's' prescribes how long mA will last. Where

For example:

Ma

mA x T = mAs 600 mA x 0.1 sec. = 60 mAs

Increasing either the mA or time will increase the quantity of radiation; therefore the amount of radiation in an examination is represented as mAs.

The reciprocity law 

The reciprocity states that a reaction of a photogenic emulsion to light will be equal to the products of the intensity of that light and the time of the exposure 1. This law pertains to mAs in the sense that all combinations of mA x T that amount to an equal quantity will produce the same amount of density. For example: 

50 mA x 1/5 sec. = 10 mAs will have the same amount of density as is equal to 300 mA x 1/30 sec. = 10 mAs

It is due to this law that radiographers will have to take into consideration all other factors (mA, focal spot, SID, kVp to reduce time to avoid motion blur. 

  • -<p><strong>Milliamperage-seconds</strong> more commonly known as <strong>mAs</strong> is a measure of radiation produced (milliamperage) over a set amount of time (seconds) via an x-ray tube. <br>It directly influences the radiographic density, when all other factors are constant.<br>An increase in mA results in a higher production of elections that are inside the X-ray tube wich will, therefore, increase the quantity of radiation; more radiation will cause more photons reaching the detector and hence the density will increase. <br>The time factor (s) is a measure of the electrons production duration in the tube; meaning 's' prescribes how long mA will last. Where:</p><h6>
  • -<br><em>Ma x T = mAs <br>600 mA x 0.1 sec. = 60 mAs</em>
  • -</h6><p>Increasing either the mA or time will increase the quantity of radiation; therefore the amount of radiation in an examination is represented as mAs.</p><h5>The reciprocity law </h5><p>The reciprocity states that a reaction of a photogenic emulsion to light will be equal to the products of the intensity of that light and the time of the exposure <sup>1</sup>. This law pertains to mAs in the sense that all combinations of mA x T that amount to an equal quantity will produce the same amount of density. <br>For example: </p><h6>
  • -<br>50 mA x 1/5 sec. = 10 mAs will have the same amount of density as <br>300 mA x 1/30 sec.  = 10 mAs </h6><p><br>It is due to this law that radiographers will have to take into consideration all other factors (mA, focal spot, SID, kVp to reduce time to avoid motion blur. </p>
  • +<p><strong>Milliamperage-seconds</strong> more commonly known as <strong>mAs</strong> is a measure of radiation produced (milliamperage) over a set amount of time (seconds) via an x-ray tube. <br>It directly influences the radiographic density, when all other factors are constant.<br>An increase in mA results in a higher production of elections that are inside the X-ray tube wich will, therefore, increase the quantity of radiation; more radiation will cause more photons reaching the detector and hence the density will increase. <br>The time factor (s) is a measure of the electrons production duration in the tube; meaning 's' prescribes how long mA will last.</p><p>For example:   </p><p><strong>mA x T = mAs </strong><br><strong>600 mA x 0.1 sec. = 60 mAs</strong></p><p>Increasing either the mA or time will increase the quantity of radiation; therefore the amount of radiation in an examination is represented as mAs.</p><h5>The reciprocity law </h5><p>The reciprocity states that a reaction of a photogenic emulsion to light will be equal to the products of the intensity of that light and the time of the exposure <sup>1</sup>. This law pertains to mAs in the sense that all combinations of mA x T that amount to an equal quantity will produce the same amount of density.</p><p><strong>50 mA x 1/5 sec. = 10 mAs</strong> is equal to <strong>300 mA x 1/30 sec. = 10 mAs</strong></p><p><br>It is due to this law that radiographers will have to take into consideration all other factors (mA, focal spot, SID, kVp to reduce time to avoid motion blur. </p>

References changed:

  • 2. Bushong Stewart C. Radiologic science for technologists. St. Louis: Elsevier Mosby, 2013.
  • 1. Bunsen R. W. and H. E. Roscoe. "Photochemical Researches.--Part V. On the Measurement of the Chemical Action of Direct and Diffuse Sunlight.". Proceedings of the Royal Society of London 12, no. 0 (1862): 306-312. <a href="http://dx.doi.org/10.1098/rspl.1862.0069" target="_blank">. doi:10.1098/rspl.1862.0069</a>.

Sections changed:

  • Imaging Technology

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